KCET · Physics · Thermal Properties of Matter
Two stars \(A\) and \(B\) radiate maximum energy at the wavelength of \(360 \mathrm{~nm}\) and \(480 \mathrm{~nm}\) respectively. Then the ratio of the surface temperatures of \(A\) and \(B\) is
- A \(3: 4\)
- B \(81: 256\)
- C \(4: 3\)
- D \(256: 81\)
Answer & Solution
Correct Answer
(C) \(4: 3\)
Step-by-step Solution
Detailed explanation
According to Wien's displacement law
\(\begin{aligned}
&\lambda T=\text { constant } \\
&\frac{T_{1}}{T_{2}}=\frac{\lambda_{2}}{\lambda_{1}}=\frac{480}{360}=\frac{4}{3}
\end{aligned}\)
\(\begin{aligned}
&\lambda T=\text { constant } \\
&\frac{T_{1}}{T_{2}}=\frac{\lambda_{2}}{\lambda_{1}}=\frac{480}{360}=\frac{4}{3}
\end{aligned}\)
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