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KCET · Physics · Electromagnetic Induction

A long solenoid has 500 turns, when a current of \(2 \mathrm{~A}\) is passed through it, the resulting magnetic flux linked with each turn of the solenoid is \(4 \times 10^{-3} \mathrm{~Wb}\), then selfinduction of the solenoid is

  1. A \(2.5 \mathrm{H}\)
  2. B \(2.0 \mathrm{H}\)
  3. C \(1.0 \mathrm{H}\)
  4. D \(4.0 \mathrm{H}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1.0 \mathrm{H}\)

Step-by-step Solution

Detailed explanation

Given, number of turns in the solenoid,
\(N=500\)
Current, \(I=2 \mathrm{~A}\)
Magnetic flux, \(\phi=4 \times 10^{-3} \mathrm{~Wb}\)
Self-inductance of coil,
\(L=\frac{N \phi}{I}=\frac{500 \times 4 \times 10^{-3}}{2}=1 \mathrm{H}\)