KCET · Chemistry · Chemical Kinetics
The rate equation for a reaction \(\mathrm{A} \rightarrow \mathrm{B}\) is \(\mathrm{r}=\mathrm{k}[\mathrm{A}]^{0}\). If the initial concentration of the reactant is \(a \mathrm{~mol} \mathrm{dm}{ }^{-3}\), the half-life period of the reaction is
- A \(\frac{\mathrm{a}}{2 \mathrm{k}}\)
- B \(\frac{\mathrm{k}}{\mathrm{a}}\)
- C \(\frac{a}{k}\)
- D \(\frac{2 \mathrm{a}}{\mathrm{k}}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{a}}{2 \mathrm{k}}\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{lc}\mathrm{A} \longrightarrow \mathrm{B} & \\ \because \quad \mathrm{r}=\mathrm{k}[\mathrm{A}]^{0} \\ \text { or } \quad \mathrm{r}=\mathrm{k} \\ \text { This is a zero order reaction. } \\ \therefore \quad \mathrm{t}_{1 / 2}=\frac{\mathrm{a}}{2 \mathrm{k}}\end{array}\)
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