KCET · Physics · Current Electricity
The \(I-V\) graph for a conductor at two different temperatures \(100^{\circ} \mathrm{C}\) and \(400^{\circ} \mathrm{C}\) is as shown in the figure. The temperature coefficient of resistance of the conductor is about (in per degree Celsius)

- A \(3 \times 10^{-5}\)
- B \(8 \times 10^{-3}\)
- C \(9 \times 10^{-3}\)
- D \(12 \times 10^{-3}\)
Answer & Solution
Correct Answer
(A) \(3 \times 10^{-5}\)
Step-by-step Solution
Detailed explanation
From the \(I-V\) graph,

Resistance of first conductor,
\(R_1=\frac{1}{\tan 45^{\circ}}=1 \Omega\)
Resistance of second conductor,
\(R_2=\frac{1}{\tan 30^{\circ}}=\sqrt{3} \Omega\)
\(\therefore\) Temperature coefficient of resistance of the conductor.
\(\alpha=\frac{R_2-R_1}{R_1 t_2-R_2 t_1}=\frac{\sqrt{3-1}}{1 \times 400-\sqrt{3} \times 100}\)
\(=3.22 \times 10^{-3} \rho \mathrm{C}=3 \times 10^{-3} /{ }^{\circ} \mathrm{C}\)

Resistance of first conductor,
\(R_1=\frac{1}{\tan 45^{\circ}}=1 \Omega\)
Resistance of second conductor,
\(R_2=\frac{1}{\tan 30^{\circ}}=\sqrt{3} \Omega\)
\(\therefore\) Temperature coefficient of resistance of the conductor.
\(\alpha=\frac{R_2-R_1}{R_1 t_2-R_2 t_1}=\frac{\sqrt{3-1}}{1 \times 400-\sqrt{3} \times 100}\)
\(=3.22 \times 10^{-3} \rho \mathrm{C}=3 \times 10^{-3} /{ }^{\circ} \mathrm{C}\)
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