KCET · Physics · Semiconductors
The circuit shown in figure contains two ideal diodes \(D_1\) and \(D_2\). If a cell of emf 3 V and negligible internal resistance is connected as shown, then the current through \(70 \Omega\) resistance, (in ampere) is
- A 0.01
- B 0.02
- C 0.03
- D 0
Answer & Solution
Correct Answer
(C) 0.03
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & D_1 \Rightarrow \text { revere biased, } \Rightarrow \text { act as open circuit } \\ & D_2 \Rightarrow \text { Forward biased } \\ & R_{c q}=30+70=100 \Omega\end{aligned}\)
\(\mathrm{I} \Rightarrow \frac{\mathrm{V}}{\mathrm{R}_{\mathrm{eq}}}=\frac{3}{100}=0.03 \mathrm{~A}\)
\(\mathrm{I} \Rightarrow \frac{\mathrm{V}}{\mathrm{R}_{\mathrm{eq}}}=\frac{3}{100}=0.03 \mathrm{~A}\)
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