KCET · Physics · Laws of Motion
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point \(O\) through strings as shown in the figure. To achieve equilibrium, the co-efficient of static friction between the block on the floor with the floor itself is
- A \(\mu=\cot \theta\)
- B \(\mu=\sin \theta\)
- C \(\mu=\tan \theta\)
- D \(\mu=\cos \theta\)
Answer & Solution
Correct Answer
(A) \(\mu=\cot \theta\)
Step-by-step Solution
Detailed explanation
\(\mathrm{T} \sin \theta=\mathrm{Mg} ...(i)\)
\(\mathrm{T} \cos \theta=\mu \mathrm{Mg}...(ii)\)
(ii) - (i) given
\(\mu=\frac{\cos \theta}{\sin \theta}=\cot \theta\)
\(\mathrm{T} \cos \theta=\mu \mathrm{Mg}...(ii)\)
(ii) - (i) given
\(\mu=\frac{\cos \theta}{\sin \theta}=\cot \theta\)
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