KCET · Physics · Magnetic Effects of Current
The average power dissipated in a pure inductor is
- A \( \frac{1}{2} \mathrm{VI} \)
- B \( \mathrm{VI}^{2} \)
- C \( \frac{\mathrm{VI}^{2}}{4} \)
- D zero
Answer & Solution
Correct Answer
(D) zero
Step-by-step Solution
Detailed explanation
Average power dissipated \( =P_{a v}=V I \cos \phi \)
In pure inductor, there is a phase difference of \( \pi / 2 \) between voltage and current. Therefore
\( \phi=\frac{\Pi}{2} \Rightarrow \cos \phi=0 \Rightarrow P_{a v}=0 \)
Thus, average power dissipated in a pure inductor is zero.
In pure inductor, there is a phase difference of \( \pi / 2 \) between voltage and current. Therefore
\( \phi=\frac{\Pi}{2} \Rightarrow \cos \phi=0 \Rightarrow P_{a v}=0 \)
Thus, average power dissipated in a pure inductor is zero.
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