KCET · Physics · Motion In One Dimension
A body falls freely for \( 10 \mathrm{sec} \). Its average velocity during this journey (take \( g=10 \mathrm{~ms}^{-2} \) )
- A \( 100 \mathrm{~ms}^{-1} \)
- B \( 10 m s^{-1} \)
- C \( 50 m s^{-1} \)
- D \( 5 \mathrm{~ms}^{-1} \)
Answer & Solution
Correct Answer
(C) \( 50 m s^{-1} \)
Step-by-step Solution
Detailed explanation
Given, body falls freely for \(t=10 s ; g=10 \mathrm{~ms}^{-2}\)
Average velocity \(=\frac{\text { Total displacement }}{\text { Total time }}\)
Now total displacement \(S=u+\frac{1}{2} g t^{2}=0+\frac{1}{2} \times 10 \times 10^{2}\)
Total displacement \(=500 \mathrm{~m}\)
Therefore, average velocity \(=\frac{500}{10}=50 \mathrm{~ms}^{-1}\)
Average velocity \(=\frac{\text { Total displacement }}{\text { Total time }}\)
Now total displacement \(S=u+\frac{1}{2} g t^{2}=0+\frac{1}{2} \times 10 \times 10^{2}\)
Total displacement \(=500 \mathrm{~m}\)
Therefore, average velocity \(=\frac{500}{10}=50 \mathrm{~ms}^{-1}\)
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