KCET · Physics · Nuclear Physics
During a \(\beta^{-}\)-decay
- A an atomic electron is ejected
- B an electron which is already present within the nucleus is ejected
- C a neutron in the nucleus decays emitting an electron
- D a proton in the nucleus decays emitting an electron
Answer & Solution
Correct Answer
(C) a neutron in the nucleus decays emitting an electron
Step-by-step Solution
Detailed explanation
The process of \(\beta^{-}\)decay is shown below
\({ }_{Z}^{A} X \stackrel{\beta^{-}}{\longrightarrow}{ }_{Z+1}^{A} Y+e^{-}+\bar{v}+\text { energy }\)
Thus, in this decay a neutron inside the nucleus decays into a proton with the emission of an electron \(e^{-}\)and a particle called anti-neutrino \((\bar{v})\).
\({ }_{Z}^{A} X \stackrel{\beta^{-}}{\longrightarrow}{ }_{Z+1}^{A} Y+e^{-}+\bar{v}+\text { energy }\)
Thus, in this decay a neutron inside the nucleus decays into a proton with the emission of an electron \(e^{-}\)and a particle called anti-neutrino \((\bar{v})\).
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