KCET · Maths · Straight Lines
The probability distribution of X is
\(\begin{array}{|c|c|c|c|c|} \hline \mathrm{X} & 0 & 1 & 2 & 3 \\ \hline \mathrm{P}(\mathrm{X}) & 0.3 & \mathrm{k} & 2 \mathrm{k} & 2 \mathrm{k} \\ \hline \end{array}\)
- A \( 0.14 \)
- B \( 0.3 \)
- C \( 0.7 \)
- D \( 11 \)
Answer & Solution
Correct Answer
(A) \( 0.14 \)
Step-by-step Solution
Detailed explanation
We know \( \sum P(X)=1 \)
So, \( \Sigma P(X)=0.3+k+2 k+2 k=1 \)
\( \Rightarrow 5 k=0.7 \Rightarrow k=0.14 \)
So, \( \Sigma P(X)=0.3+k+2 k+2 k=1 \)
\( \Rightarrow 5 k=0.7 \Rightarrow k=0.14 \)
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