KCET · Chemistry · Chemistry in Everyday Life
A reaction has both \( \Delta \mathrm{H} \) and \( \Delta \mathrm{S} \) - ve. The rate of reaction
- A increases with increase in temperature
- B increases with decrease in temperature
- C remains unaffected by change in temperature
- D cannot be predicted for change in temperature
Answer & Solution
Correct Answer
(B) increases with decrease in temperature
Step-by-step Solution
Detailed explanation
The reaction is thermodynamic ally favored when \( \Delta G < 0 \)
\[
\begin{array}{l}
\Delta G=\Delta H-T \Delta S \\
\Delta G=-v e-T(-v e) \\
\Delta G=-v e+T(+v e)
\end{array}
\]
Therefore, on increasing the temperature \( \Delta \mathrm{G} \) becomes positive (+ve). Hence, the rate of reaction increases with
decrease in temperature.
\[
\begin{array}{l}
\Delta G=\Delta H-T \Delta S \\
\Delta G=-v e-T(-v e) \\
\Delta G=-v e+T(+v e)
\end{array}
\]
Therefore, on increasing the temperature \( \Delta \mathrm{G} \) becomes positive (+ve). Hence, the rate of reaction increases with
decrease in temperature.
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