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KCET · Maths · Vector Algebra

The component of \(\mathbf{i}\) in the direction of the vector \(\hat{\mathbf{i}}+\hat{\mathbf{j}}+2 \hat{\mathbf{k}}\) is

  1. A \(6\)
  2. B \(6 \sqrt{6}\)
  3. C \(\frac{\sqrt{6}}{6}\)
  4. D \(\sqrt{6}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{\sqrt{6}}{6}\)

Step-by-step Solution

Detailed explanation

We know that component of a in the direction
of \(\mathbf{b}\) is
\(\frac{|\mathbf{a} \cdot \mathbf{b}|}{|\mathbf{b}|^2}\)
Let \(\mathbf{b}=\hat{\mathbf{i}}+\hat{\mathbf{j}}+2 \hat{\mathbf{k}}\) and \(\mathbf{a}=\hat{\mathbf{i}}\)
Then, we have \(|\mathbf{a} \cdot \mathbf{b}|=1\)
and \(|\mathbf{b}|=\sqrt{6}\)
Now, the component of \(i\) in the direction \(\hat{\mathbf{i}}+\hat{\mathbf{j}}+2 \hat{\mathbf{k}}\) is \(\frac{1}{\sqrt{6}}=\frac{\sqrt{6}}{6}\)