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KCET · Maths · Functions

The domain of the function \(\sqrt{\dfrac{x-7}{9-x}}\) is

  1. A \([7, 9]\)
  2. B \([7, 9)\)
  3. C \((7, 9]\)
  4. D \((7, 9)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \([7, 9)\)

Step-by-step Solution

Detailed explanation

For the function to be defined, the expression inside the square root must be non-negative and the denominator must not be zero.

\(\dfrac{x-7}{9-x} \ge 0\) and \(9-x \ne 0\)

Multiplying the numerator and denominator by \(-1\), we get:

\(\dfrac{x-7}{x-9} \le 0\)

The critical points are \(x = 7\) and \(x = 9\).

Using the wavy curve method, the expression \(\dfrac{x-7}{x-9}\) is less than or equal to zero for \(x \in [7, 9]\).

Since the denominator cannot be zero, \(x \ne 9\).

Therefore, the domain of the function is \(x \in [7, 9)\).

Answer: \([7, 9)\)