KCET · Maths · Mathematical Reasoning
In the group \(G=\{0,1,2,3,4,5\}\) under addition modulo \(6,\left(2+{ }_{6} 3^{-1}+{ }_{6} 4\right)^{-1}\) is equal to
- A 2
- B 3
- C 5
- D 0
Answer & Solution
Correct Answer
(B) 3
Step-by-step Solution
Detailed explanation
\(\begin{aligned}\left(2+{ }_{6} 3^{-1}+{ }_{6} 4\right)^{-1} &=\left(2+{ }_{6} 3+{ }_{6} 4\right)^{-1} \quad\left(\because 3^{-1}=3\right) \\ &=\left(5+{ }_{6} 4\right)^{-1}=(3)^{-1} \\ &=3 \end{aligned}\)
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