KCET · Maths · Basic of Mathematics
On the set of positive rationals, a binary operation * is defined by \( a^{*} b=\frac{2 a b}{5} \). If \( 2^{*} x=3^{-1} \)
then \( x= \)
- A \( \frac{5}{12} \)
- B \( \frac{125}{48} \)
- C \( \frac{1}{6} \)
- D \( \frac{2}{5} \)
Answer & Solution
Correct Answer
(B) \( \frac{125}{48} \)
Step-by-step Solution
Detailed explanation
(B)
\[
\begin{array}{l}
a^{*} e=a \\
a^{*} e=a \Rightarrow \frac{2 a e}{5}=a \Rightarrow e=\frac{5}{2} \\
a^{*} a^{-1}=e \Rightarrow \frac{2 a a^{-1}}{5}=\frac{5}{2} \Rightarrow a^{-1}=\frac{25}{4 a} \\
2^{*} x=3^{-1} \Rightarrow \frac{2(2 x)}{5}=\frac{25}{4(3)} \\
\Rightarrow x=\frac{125}{48}
\end{array}
\]
\[
\begin{array}{l}
a^{*} e=a \\
a^{*} e=a \Rightarrow \frac{2 a e}{5}=a \Rightarrow e=\frac{5}{2} \\
a^{*} a^{-1}=e \Rightarrow \frac{2 a a^{-1}}{5}=\frac{5}{2} \Rightarrow a^{-1}=\frac{25}{4 a} \\
2^{*} x=3^{-1} \Rightarrow \frac{2(2 x)}{5}=\frac{25}{4(3)} \\
\Rightarrow x=\frac{125}{48}
\end{array}
\]
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