KCET · Maths · Probability
Two letters are chosen from the letters of the word 'EQUATIONS'. The probability that one is
vowel and the other is consonant is
- A \( \frac{4}{9} \)
- B \( \frac{5}{9} \)
- C \( \frac{8}{9} \)
- D \( \frac{3}{9} \)
Answer & Solution
Correct Answer
(B) \( \frac{5}{9} \)
Step-by-step Solution
Detailed explanation
(B)
9 Letters word
vowels \(=5\)
consonants \(=4\)
\(P(1\) vowel and 1 consonant \()=\frac{{ }^{5} C_{1} \times{ }^{4} C_{1}}{{ }^{9} C_{2}}=\frac{5 \times 4}{\frac{9 \times 8}{2}}\)
9 Letters word
vowels \(=5\)
consonants \(=4\)
\(P(1\) vowel and 1 consonant \()=\frac{{ }^{5} C_{1} \times{ }^{4} C_{1}}{{ }^{9} C_{2}}=\frac{5 \times 4}{\frac{9 \times 8}{2}}\)
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