KCET · Maths · Statistics
The coefficient of variation of two distributions are \( 60 \) and \( 70 \). The standard deviation are \( 21 \)
and \( 16 \) respectively, then their mean is
- A 35
- B \( 23 \)
- C \( 28.25 \)
- D \( 22.85 \)
Answer & Solution
Correct Answer
(C) \( 28.25 \)
Step-by-step Solution
Detailed explanation
Given that, \(C V_{x}=60 \rightarrow(1)\)
We know that, \(C V=\frac{\sigma}{\chi} \times 100\)
So, \(\frac{21}{x} \times 100=60\)
\(\Rightarrow \bar{\chi}=\frac{2100}{60}=35\)
Again, \(C V_{y}=70\)
\(\frac{16}{y} \times 100=70\) \(\Rightarrow \bar{y}=\frac{1600}{70}=22.86\)
So, mean of two means are
\(\frac{\bar{x}+\bar{y}}{2}\) \(\frac{35+22.86}{2}=28.925\)
We know that, \(C V=\frac{\sigma}{\chi} \times 100\)
So, \(\frac{21}{x} \times 100=60\)
\(\Rightarrow \bar{\chi}=\frac{2100}{60}=35\)
Again, \(C V_{y}=70\)
\(\frac{16}{y} \times 100=70\) \(\Rightarrow \bar{y}=\frac{1600}{70}=22.86\)
So, mean of two means are
\(\frac{\bar{x}+\bar{y}}{2}\) \(\frac{35+22.86}{2}=28.925\)
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