KCET · Maths · Sets and Relations
If \( U \) is the universal set with \( 100 \) elements; \( A \) and \( B \) are two sets such that \( n(A)=50, n(B)=60 \),
\( n(A \cap B)=20 \) then \( n\left(A^{\prime} \cap B^{\prime}\right)= \)
- A \( 20 \)
- B \( 10 \)
- C \( 40 \)
- D \( 90 \)
Answer & Solution
Correct Answer
(B) \( 10 \)
Step-by-step Solution
Detailed explanation
\((B)\)
\(n(U)=100\)
\(n(A)=50\)
\(n(B)=60\)
\(n(A \cap B)=20\)
\(n(A \cup B)=n(A)+n(B)-n(A \cap B)\)
\(=50+60-20\)
\(=110-20\)
\(=90\)
\(n\left(A^{\prime} \cap B^{\prime}\right)=n(A \cup B)^{\prime}\)
\(=n(U)-n(A \cup B)\)
\(=100-90\)
\(=10\)
\(n(U)=100\)
\(n(A)=50\)
\(n(B)=60\)
\(n(A \cap B)=20\)
\(n(A \cup B)=n(A)+n(B)-n(A \cap B)\)
\(=50+60-20\)
\(=110-20\)
\(=90\)
\(n\left(A^{\prime} \cap B^{\prime}\right)=n(A \cup B)^{\prime}\)
\(=n(U)-n(A \cup B)\)
\(=100-90\)
\(=10\)
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