KCET · Chemistry · General Organic Chemistry
\(1.2 \mathrm{~g}\) of organic compound of Kjeldahlization liberates ammonia which consumes \(30 \mathrm{~cm}^{3}\) of \(1 \mathrm{~N} \mathrm{HCl}\). The percentage of nitrogen in the organic compound is
- A 30
- B 35
- C \(46.67\)
- D \(20.8\)
Answer & Solution
Correct Answer
(B) 35
Step-by-step Solution
Detailed explanation
Percentage of nitrogen
\[
\begin{aligned}
&=\frac{1.4 \times \mathrm{N} \text { of acid } \times \mathrm{Vol} \text {. used with } \mathrm{NH}_{3}}{\text { Weight of organic compound }} \\
&=\frac{1.4 \times 1 \times 30}{1.2} \\
&=35
\end{aligned}
\]
\[
\begin{aligned}
&=\frac{1.4 \times \mathrm{N} \text { of acid } \times \mathrm{Vol} \text {. used with } \mathrm{NH}_{3}}{\text { Weight of organic compound }} \\
&=\frac{1.4 \times 1 \times 30}{1.2} \\
&=35
\end{aligned}
\]
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