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KCET · Maths · Vector Algebra

If \(\vec{a}=\hat{i}+2 \hat{j}+\hat{k}, \vec{b}=\hat{i}-\hat{j}+4 \hat{k}\) and \(\vec{c}=\hat{i}+\hat{j}+\hat{k}\) are such that \(\vec{a}+\lambda \vec{b}\) is perpendicular to \(\vec{c}\), then the value of \(\lambda\) is

  1. A \(1\)
  2. B \(\pm 1\)
  3. C \(-1\)
  4. D \(0\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-1\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & (\overrightarrow{\mathrm{a}}+\lambda \overrightarrow{\mathrm{b}}) \perp \mathrm{c} \\ & (\overrightarrow{\mathrm{a}}+\lambda \overrightarrow{\mathrm{b}}) \cdot \overrightarrow{\mathrm{c}}=0 \\ & \lambda+1+2+\lambda+4 \lambda+1=0, \lambda+1 \Rightarrow \lambda=-1\end{aligned}\)