KCET · Maths · Vector Algebra
If \(\vec{a}=\hat{i}+2 \hat{j}+\hat{k}, \vec{b}=\hat{i}-\hat{j}+4 \hat{k}\) and \(\vec{c}=\hat{i}+\hat{j}+\hat{k}\) are such that \(\vec{a}+\lambda \vec{b}\) is perpendicular to \(\vec{c}\), then the value of \(\lambda\) is
- A \(1\)
- B \(\pm 1\)
- C \(-1\)
- D \(0\)
Answer & Solution
Correct Answer
(C) \(-1\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & (\overrightarrow{\mathrm{a}}+\lambda \overrightarrow{\mathrm{b}}) \perp \mathrm{c} \\ & (\overrightarrow{\mathrm{a}}+\lambda \overrightarrow{\mathrm{b}}) \cdot \overrightarrow{\mathrm{c}}=0 \\ & \lambda+1+2+\lambda+4 \lambda+1=0, \lambda+1 \Rightarrow \lambda=-1\end{aligned}\)
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