ExamBro
ExamBro
KCET · Maths · Functions

The local minimum value of the function \(f^{\prime}\) given by \(f(x)=3+|x|\), \(x \in R\) is.

  1. A \( \square 3 \)
  2. B \( \square 0 \)
  3. C \( \square -3 \)
  4. D \( \square 1 \)
Verified Solution

Answer & Solution

Correct Answer

(D) \( \square 1 \)

Step-by-step Solution

Detailed explanation

Given that, \(f(x)=3+|x|\) We know that \(|x|=\sqrt{x^{2}}\) So, \(f(x)=3+\sqrt{x^{2}}\)
So, \(f^{\prime}(x)=\frac{2 x}{2 \sqrt{x^{2}}}=\frac{x}{|x|}\)


Clearly when \(x>0\),local minimum \(=1\)
When \(x < 0\), local minimum \(=-1\)
So, option (3) and (4) both are true