KCET · Maths · Vector Algebra
If \( |\bar{a}| \) and \( |\bar{b}| \) are mutually perpendicular unit vectors, then
\( (3|\bar{a}|+2|\bar{b}|) \cdot(5|\bar{a}|-6|\bar{b}|)= \)
- A 5
- B \( 03 \)
- C \( 06 \)
- D \( 12 \)
Answer & Solution
Correct Answer
(B) \( 03 \)
Step-by-step Solution
Detailed explanation
Given that, \((3 \vec{a}+2 \vec{b}) \cdot(5 \vec{a}-6 \vec{b})\)
Since, \(\vec{a} \cdot \vec{b}=0\)
and \(|\vec{a}|=|\vec{b}|=3\)
Then \((3 \vec{a}+2 \vec{b}) \cdot(5 \vec{a}-6 \vec{b})\)
\(=15|\vec{a}|^{2}-18(0)+10(0)-12|\vec{b}|^{2}=3\)
Since, \(\vec{a} \cdot \vec{b}=0\)
and \(|\vec{a}|=|\vec{b}|=3\)
Then \((3 \vec{a}+2 \vec{b}) \cdot(5 \vec{a}-6 \vec{b})\)
\(=15|\vec{a}|^{2}-18(0)+10(0)-12|\vec{b}|^{2}=3\)
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