KCET · Chemistry · Carboxylic Acid Derivatives
Ethanoic acid undergoes Hell-Volhard Zelinsky reaction but methanoic acid does not, because of
- A presence of \(\alpha-\mathrm{H}\) atom in ethanoic acid
- B absence of \(\alpha-\mathrm{H}\) atom in ethanoic acid
- C higher acidic strength of ethanoic acid than methanoic acid
- D presence of \(\alpha-\mathrm{H}\) atom in methanoic acid
Answer & Solution
Correct Answer
(A) presence of \(\alpha-\mathrm{H}\) atom in ethanoic acid
Step-by-step Solution
Detailed explanation
Ethanoic acid has \(\alpha-\mathrm{H}\) atom, thus it undergoes Hell-Volhard Zelinsky reaction. Whereas methanoic acid does not has \(\alpha-\mathrm{H}\) atom, thus it does not give this test.
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