KCET · Maths · Functions
The middle term of expansion of \( \left(\frac{10}{x}+\frac{x}{10}\right)^{10} \)
- A \( {}^{7} C_{5} \)
- B \( { }_{0}^{8} C_{5} \)
- C \( { }_{0}^{9} C_{5} \)
- D \( { }^{10}{ }^{10} C_{5} \)
Answer & Solution
Correct Answer
(D) \( { }^{10}{ }^{10} C_{5} \)
Step-by-step Solution
Detailed explanation
Given expression, \( \left(\frac{10}{x}+\frac{x}{10}\right)^{10} \)
here \( n=10 \). So, middle term is \( 6 \) th term
Therefore, \( T_{6}={ }^{10} C_{5}\left(\frac{10}{\chi}\right)^{5}\left(\frac{\chi}{10}\right)^{5}={ }^{10} C_{5} \)
here \( n=10 \). So, middle term is \( 6 \) th term
Therefore, \( T_{6}={ }^{10} C_{5}\left(\frac{10}{\chi}\right)^{5}\left(\frac{\chi}{10}\right)^{5}={ }^{10} C_{5} \)
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