KCET · Maths · Inverse Trigonometric Functions
\(\sin \left(2 \sin ^{-1} \sqrt{\frac{63}{65}}\right)\) is equal to
- A \(\frac{2 \sqrt{126}}{65}\)
- B \(\frac{4 \sqrt{65}}{65}\)
- C \(\frac{8 \sqrt{63}}{65}\)
- D \(\frac{\sqrt{63}}{65}\)
Answer & Solution
Correct Answer
(A) \(\frac{2 \sqrt{126}}{65}\)
Step-by-step Solution
Detailed explanation
\(\sin \left(2 \sin ^{-1} \sqrt{\frac{63}{65}}\right)=\sin \left(\sin ^{-1} 2 \sqrt{\frac{63}{65}} \sqrt{1-\frac{63}{65}}\right)\)
\[
\begin{aligned}
&=\sin (\sin \\
&=\sin (\sin \\
&=\frac{2 \sqrt{126}}{65}
\end{aligned}
\]
\[
\begin{aligned}
&=\sin (\sin \\
&=\sin (\sin \\
&=\frac{2 \sqrt{126}}{65}
\end{aligned}
\]
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