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KCET · Maths · Differential Equations

The number of solutions of \(\frac{d y}{d x}=\frac{y+1}{x-1}\), when \(y(\mathrm{l})=2\) is

  1. A three
  2. B one
  3. C infinite
  4. D two
Verified Solution

Answer & Solution

Correct Answer

(B) one

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}=\frac{y+1}{x-1}\)
\(\Rightarrow \quad \frac{1}{x-1} d x=\frac{1}{y+1} d y\)
Integrating both sides,
\(\int \frac{1}{x-1} d x=\int \frac{1}{y+1} d y\)
\(\Rightarrow \quad \log |x-1|=\log |y+1|+\log C\)
\(\Rightarrow \quad(x-1)=c(y+1)\)
As, \(\quad y(1)=2\),
\(0=c(3)\)
\(\Rightarrow \quad c=0\)
Hence, \(x-1=0\) or \(x=1\)
The given differential equation has only one solution.