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KCET · Maths · Limits

\(\lim _{n \rightarrow \infty} \frac{3 \cdot 2^{n+1}-4 \cdot 5^{n+1}}{5 \cdot 2^{n}+7 \cdot 5^{n}}\) is equal to

  1. A \(\frac{3}{5}\)
  2. B \(-\frac{4}{7}\)
  3. C \(-\frac{20}{7}\)
  4. D 0
Verified Solution

Answer & Solution

Correct Answer

(C) \(-\frac{20}{7}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} \lim _{n \rightarrow \infty} \frac{3 \cdot 2^{n+1}-4 \cdot 5^{n+1}}{5 \cdot 2^{n}+7 \cdot 5^{n}} \\ &=\lim _{n \rightarrow \infty} \frac{5^{n}\left(6 \cdot\left(\frac{2}{5}\right)^{n}-20\right)}{5^{n}\left(5 \cdot\left(\frac{2}{5}\right)^{n}+7\right)} \\ &=-\frac{20}{7} \end{aligned}\)