KCET · Chemistry · Thermodynamics (C)
When the same quantity of heat is absorbed by a system at two different temperatures \(T_{1}\) and \(T_{2}\), such that \(T_{1}>T_{2}\), change in entropies are \(\Delta S_{1}\) and \(\Delta S_{2}\) respectively. Then
- A \(\Delta S_{1} < \Delta S_{2}\)
- B \(\Delta S_{1}=\Delta S_{2}\)
- C \(S_{1}>S_{2}\)
- D \(\Delta S_{2} < \Delta S_{1}\)
Answer & Solution
Correct Answer
(A) \(\Delta S_{1} < \Delta S_{2}\)
Step-by-step Solution
Detailed explanation
We know, \(\Delta S=\frac{q_{\mathrm{rev}}}{T}\)
Here, \(\Delta S_{1}=\frac{q_{\mathrm{rev}}}{T_{1}}\) and \(\Delta S_{2}=\frac{q_{\mathrm{rev}}}{T_{2}}\)
Here, \(q_{\text {rev }}\) is same in both the cases and \(T_{1}>T_{2}\) When denominator is larger, the value is lesses.
So, \(\Delta S_{1} < \Delta S_{2}\)
Here, \(\Delta S_{1}=\frac{q_{\mathrm{rev}}}{T_{1}}\) and \(\Delta S_{2}=\frac{q_{\mathrm{rev}}}{T_{2}}\)
Here, \(q_{\text {rev }}\) is same in both the cases and \(T_{1}>T_{2}\) When denominator is larger, the value is lesses.
So, \(\Delta S_{1} < \Delta S_{2}\)
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