KCET · Chemistry · Aldehydes and Ketones
Match List-I with List-II and select the correct options
| List-I (Functional group) | List-II (Functional group reagent) | ||
|---|---|---|---|
| (a) |  | (i) | Neutral ferric chloride test |
| (b) | \(\text{C}_6\text{H}_5\text{NH}_2\) | (ii) | Azo dye test |
| (c) | \(\text{CH}_3\text{CH}_2\text{CHO}\) | (iii) | Ceric ammonium nitrate test |
| (d) |  | (iv) | Tollen's reagent test |
- A a-iv, b-i, c-ii, d–iii
- B a-iii, b-ii, c-iv, d–i
- C a-iii, b-ii, c-i, d–iv
- D a-ii, b-iii, c-iv, d–i
Answer & Solution
Correct Answer
(B) a-iii, b-ii, c-iv, d–i
Step-by-step Solution
Detailed explanation
(a) The first compound is 2-butanol, which is an aliphatic alcohol. Aliphatic alcohols give a positive ceric ammonium nitrate test, producing a red colouration. Thus, (a) matches with (iii).
(b) \(\text{C}_6\text{H}_5\text{NH}_2\) is aniline, a primary aromatic amine. It gives a positive azo dye test by reacting with nitrous acid to form a diazonium salt, which couples with \(\beta\)-naphthol to form an orange-red dye. Thus, (b) matches with (ii).
(c) \(\text{CH}_3\text{CH}_2\text{CHO}\) is propanal, an aldehyde. Aldehydes reduce Tollen's reagent to form a silver mirror. Thus, (c) matches with (iv).
(d) The second compound is phenol. Phenols react with neutral \(\text{FeCl}_3\) solution to give a characteristic violet colouration. Thus, (d) matches with (i).
The correct matching is a-iii, b-ii, c-iv, d-i.
Answer: a-iii, b-ii, c-iv, d–i
(b) \(\text{C}_6\text{H}_5\text{NH}_2\) is aniline, a primary aromatic amine. It gives a positive azo dye test by reacting with nitrous acid to form a diazonium salt, which couples with \(\beta\)-naphthol to form an orange-red dye. Thus, (b) matches with (ii).
(c) \(\text{CH}_3\text{CH}_2\text{CHO}\) is propanal, an aldehyde. Aldehydes reduce Tollen's reagent to form a silver mirror. Thus, (c) matches with (iv).
(d) The second compound is phenol. Phenols react with neutral \(\text{FeCl}_3\) solution to give a characteristic violet colouration. Thus, (d) matches with (i).
The correct matching is a-iii, b-ii, c-iv, d-i.
Answer: a-iii, b-ii, c-iv, d–i
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