KCET · Chemistry · Hydrocarbons
If Aniline is treated with \( 1: 1 \) mixture of conc. \( \mathrm{HNO}_{3} \) and con. \( \mathrm{H} 2 \mathrm{SO}_{4}, \mathrm{p} \)-nitroaniline and \( \mathrm{m} \) -
nitroaniline are formed nearly in equal amounts. This is due to
- A \( \mathrm{m} \& \mathrm{p} \) directing property of \( -\mathrm{NH}_{2} \) group.
- B isomerization of some p-nitroaniline into m-nitroaniline.
- C m-directing property of \( -\mathrm{NH}_{2} \) group.
- D protonation of \( -\mathrm{NH}_{2} \) which causes deactivation of benzene ring.
Answer & Solution
Correct Answer
(D) protonation of \( -\mathrm{NH}_{2} \) which causes deactivation of benzene ring.
Step-by-step Solution
Detailed explanation
(D)
In presence of acid aniline gets protonated to anilinium ion which is meta directing.
In presence of acid aniline gets protonated to anilinium ion which is meta directing.
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