KCET · Chemistry · Practical Chemistry
When salt BA is treated with Conc. \(\text{H}_2\text{SO}_4\) reddish brown gas is liberated. The aqueous solution of BA gives pale yellow precipitate with \(\text{AgNO}_3\) solution. Which of the following anion (\(\text{A}^-\)) is present in the salt BA?
- A \(\text{Cl}^-\)
- B \(\text{CO}_3^{2-}\)
- C \(\text{SO}_4^{2-}\)
- D \(\text{Br}^-\)
Answer & Solution
Correct Answer
(D) \(\text{Br}^-\)
Step-by-step Solution
Detailed explanation
When a salt containing bromide ion (\(\text{Br}^-\)) is treated with concentrated \(\text{H}_2\text{SO}_4\), reddish-brown bromine gas (\(\text{Br}_2\)) is evolved due to the oxidation of bromide ions by sulphuric acid.
The reaction is: \(2\text{Br}^- + 2\text{H}_2\text{SO}_4 \rightarrow \text{Br}_2 \uparrow + \text{SO}_2 + \text{SO}_4^{2-} + 2\text{H}_2\text{O}\).
When an aqueous solution of a bromide salt is treated with \(\text{AgNO}_3\) solution, a pale yellow precipitate of silver bromide (\(\text{AgBr}\)) is formed.
The reaction is: \(\text{Br}^- + \text{Ag}^+ \rightarrow \text{AgBr} \downarrow\).
Therefore, the anion \(\text{A}^-\) present in the salt BA is \(\text{Br}^-\).
Answer: \(\text{Br}^-\)
The reaction is: \(2\text{Br}^- + 2\text{H}_2\text{SO}_4 \rightarrow \text{Br}_2 \uparrow + \text{SO}_2 + \text{SO}_4^{2-} + 2\text{H}_2\text{O}\).
When an aqueous solution of a bromide salt is treated with \(\text{AgNO}_3\) solution, a pale yellow precipitate of silver bromide (\(\text{AgBr}\)) is formed.
The reaction is: \(\text{Br}^- + \text{Ag}^+ \rightarrow \text{AgBr} \downarrow\).
Therefore, the anion \(\text{A}^-\) present in the salt BA is \(\text{Br}^-\).
Answer: \(\text{Br}^-\)
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