KCET · Chemistry · Coordination Compounds
The correct order for wavelengths of light absorbed in the complex ions \(\left[\operatorname{CoCl}\left(\mathrm{NH}_{3}\right)_{5}\right]^{2+},\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\) and \(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\) is
- A \(\left[\mathrm{CoCl}\left(\mathrm{NH}_{3}\right)_{5}\right]^{2+}>\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\)
- B \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}>\left[\mathrm{CoCl}\left(\mathrm{NH}_{3}\right)_{5}\right]^{2+}\)
- C \(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}>\left[\mathrm{CoCl}\left(\mathrm{NH}_{3}\right)_{5}\right]^{2+}>\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\)
- D \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{CoCl}\left(\mathrm{NH}_{3}\right)_{5}\right]^{2+}>\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\)
Answer & Solution
Correct Answer
(A) \(\left[\mathrm{CoCl}\left(\mathrm{NH}_{3}\right)_{5}\right]^{2+}>\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\)
Step-by-step Solution
Detailed explanation
Wavelengths of light absorbed is inversely proportional to strength of the ligand and order of strength of the given ligand is \(\mathrm{CN}^{-}>\mathrm{NH}_{3}>\mathrm{Cl}^{-}\).
Therefore, the correct order for wavelength of light absorbed in the complex ions is \(\left[\operatorname{CoCl}\left(\mathrm{NH}_{3}\right)_{5}\right]^{2+}>\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\)
Therefore, the correct order for wavelength of light absorbed in the complex ions is \(\left[\operatorname{CoCl}\left(\mathrm{NH}_{3}\right)_{5}\right]^{2+}>\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\)
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