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KCET · Physics · Nuclear Physics

In the following equation representing \(\beta^{-}\) decay, the number of neutrons in the nucleus \(X\) is
\({ }_{83}^{210} \mathrm{Bi} \longrightarrow X+e^{-1}+\bar{v}\)

  1. A \(126\)
  2. B \(127\)
  3. C \(125\)
  4. D \(84\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(126\)

Step-by-step Solution

Detailed explanation

In \(\beta^{-}\)decay, reaction is given as,
\({ }_{83}^{210} \mathrm{Bi} \longrightarrow{ }_{84}^{210} X+e^{-1}+\overline{\mathrm{v}}\)
\(\therefore\) Number of neutrons \(=210-84=126\)
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