KCET · Physics · Nuclear Physics
In the following equation representing \(\beta^{-}\) decay, the number of neutrons in the nucleus \(X\) is
\({ }_{83}^{210} \mathrm{Bi} \longrightarrow X+e^{-1}+\bar{v}\)
- A \(126\)
- B \(127\)
- C \(125\)
- D \(84\)
Answer & Solution
Correct Answer
(A) \(126\)
Step-by-step Solution
Detailed explanation
In \(\beta^{-}\)decay, reaction is given as,
\({ }_{83}^{210} \mathrm{Bi} \longrightarrow{ }_{84}^{210} X+e^{-1}+\overline{\mathrm{v}}\)
\(\therefore\) Number of neutrons \(=210-84=126\)
\({ }_{83}^{210} \mathrm{Bi} \longrightarrow{ }_{84}^{210} X+e^{-1}+\overline{\mathrm{v}}\)
\(\therefore\) Number of neutrons \(=210-84=126\)
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