KCET · Physics · Thermodynamics
An ideal gas is taken path as shown in figure. The net work done in the whole cycle is
- A \(3 p_{1} V_{1}\)
- B \(-3 \mathrm{p}_{1} \mathrm{~V}_{1}\)
- C \(6 p_{1} V_{1}\)
- D Zero
Answer & Solution
Correct Answer
(B) \(-3 \mathrm{p}_{1} \mathrm{~V}_{1}\)
Step-by-step Solution
Detailed explanation
The net work done in the whole cycle is
\(=\frac{1}{2} \times\left(3 \mathrm{p}_{1}\right) \times\left(2 \mathrm{~V}_{1}\right)=3 \mathrm{p}_{1} \mathrm{~V}_{1}\)
If the cycle is anticlockwise work done is negative
\(\therefore \mathrm{W}_{\text {cycle}}=-3 \mathrm{p}_{1} \mathrm{~V}_{1}\)
\(=\frac{1}{2} \times\left(3 \mathrm{p}_{1}\right) \times\left(2 \mathrm{~V}_{1}\right)=3 \mathrm{p}_{1} \mathrm{~V}_{1}\)
If the cycle is anticlockwise work done is negative
\(\therefore \mathrm{W}_{\text {cycle}}=-3 \mathrm{p}_{1} \mathrm{~V}_{1}\)
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