KCET · Chemistry · Some Basic Concepts of Chemistry
Three moles of \(\mathrm{PCl}_{5}\), three moles of \(\mathrm{PCl}_{3}\) and two moles of \(\mathrm{Cl}_{2}\) are taken in a closed vessel. If at equilibrium the vessel has \(1.5\) moles of \(\mathrm{PCl}_{5}\), the number of moles of \(\mathrm{PCl}_{3}\) present in it is
- A 5
- B 3
- C 6
- D \(4.5\)
Answer & Solution
Correct Answer
(D) \(4.5\)
Step-by-step Solution
Detailed explanation
\(\mathrm{PCl}_{5} \rightleftharpoons \mathrm{PCl}_{3}+\mathrm{Cl}_{2}\) \(3 \mathrm{~mol} \quad 3 \mathrm{~mol} \quad 2 \mathrm{~mol}\) initially \((3-x) \mathrm{mol} \quad(3+\mathrm{x}) \mathrm{mol} \quad(2+\mathrm{x}) \mathrm{mol}\) at equilibrium
\(\because\)
\[ 3-x=1.5 \]
\[
x=1.5
\]
Number of moles of \(\mathrm{PCl}_{3}=3+\mathrm{x}\)
\[
=3+1.5=4.5
\]
\(\because\)
\[ 3-x=1.5 \]
\[
x=1.5
\]
Number of moles of \(\mathrm{PCl}_{3}=3+\mathrm{x}\)
\[
=3+1.5=4.5
\]
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