KCET · Chemistry · Aldehydes and Ketones
The compound that does not answer iodoform test is
- A Ethanal
- B Acetone
- C Ethanoic acid
- D Acetophenone
Answer & Solution
Correct Answer
(C) Ethanoic acid
Step-by-step Solution
Detailed explanation
The iodoform test is given by compounds containing a \(CH_3-CO-\) group (methyl ketones and acetaldehyde) or a \(CH_3-CH(OH)-\) group (which can be oxidized to a methyl ketone).
Ethanal (\(CH_3CHO\)) contains a \(CH_3-CO-\) group, hence it gives the iodoform test.
Acetone (\(CH_3COCH_3\)) contains a \(CH_3-CO-\) group, hence it gives the iodoform test.
Acetophenone (\(C_6H_5COCH_3\)) contains a \(CH_3-CO-\) group, hence it gives the iodoform test.
Ethanoic acid (\(CH_3COOH\)) is a carboxylic acid. In the presence of the basic reagent (\(NaOH + I_2\)), it undergoes an acid-base reaction to form the acetate ion (\(CH_3COO^-\)), which does not undergo the haloform reaction. Thus, it does not give the iodoform test.
Answer: Ethanoic acid
Ethanal (\(CH_3CHO\)) contains a \(CH_3-CO-\) group, hence it gives the iodoform test.
Acetone (\(CH_3COCH_3\)) contains a \(CH_3-CO-\) group, hence it gives the iodoform test.
Acetophenone (\(C_6H_5COCH_3\)) contains a \(CH_3-CO-\) group, hence it gives the iodoform test.
Ethanoic acid (\(CH_3COOH\)) is a carboxylic acid. In the presence of the basic reagent (\(NaOH + I_2\)), it undergoes an acid-base reaction to form the acetate ion (\(CH_3COO^-\)), which does not undergo the haloform reaction. Thus, it does not give the iodoform test.
Answer: Ethanoic acid
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