KCET · Chemistry · Coordination Compounds
The spin only magnetic moment of \(\mathrm{Fe}^{2+}\) ion (in BM) is approximately
- A 4
- B 7
- C 5
- D 6
Answer & Solution
Correct Answer
(C) 5
Step-by-step Solution
Detailed explanation
\[
\mathrm{Fe}^{2+}-[\mathrm{Ar}] 3 d^{6}
\]
It has 4 unpaired electrons
\[
\begin{aligned}
\mu &=\sqrt{n(n+2)} \\
&=\sqrt{4(4+2)} \\
&=\sqrt{24} \\
\mu &=4.89 \mathrm{BM} \approx 5 \mathrm{BM}
\end{aligned}
\]
\mathrm{Fe}^{2+}-[\mathrm{Ar}] 3 d^{6}
\]
It has 4 unpaired electrons
\[
\begin{aligned}
\mu &=\sqrt{n(n+2)} \\
&=\sqrt{4(4+2)} \\
&=\sqrt{24} \\
\mu &=4.89 \mathrm{BM} \approx 5 \mathrm{BM}
\end{aligned}
\]
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