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KCET · Maths · Definite Integration

The solution set of the inequation \( \frac{x^{2}+6 x-7}{|x+4|} < 0 \) is

  1. A \( (-7,1) \)
  2. B \( (-7,-4) \)
  3. C \((-7,-4) \cup(-4,1) \)
  4. D \((-7,-4) \cup(4,1) \)
Verified Solution

Answer & Solution

Correct Answer

(C) \((-7,-4) \cup(-4,1) \)

Step-by-step Solution

Detailed explanation

Given that \(\frac{x^{2}+6 x-7}{|x+4|} < 0\)
So, \(x \neq 4\)
Then, \(x^{2}+6 x-7 < 0\)
\(\Rightarrow(x+7)(x-1) < 0\)
\(-7 < x < 1\)
Therefore, solutions is \((-7,-4) \cup(-4,1)\)