KCET · Physics · Semiconductors
For a transistor, \(\beta=100\). The value of \(\alpha\) is
- A \(0.01\)
- B \(1.01\)
- C \(0.99\)
- D 100
Answer & Solution
Correct Answer
(C) \(0.99\)
Step-by-step Solution
Detailed explanation
We have,
\[
\alpha=\frac{\beta}{1+\beta}=\frac{100}{101}=0.99
\]
\[
\alpha=\frac{\beta}{1+\beta}=\frac{100}{101}=0.99
\]
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