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KCET · Maths · Determinants

A box contains \( 6 \) red marbles numbers from \( 1 \) through \( 6 \) and \( 4 \) white marbles \( 12 \) through \( 15 . \)
Find the probability that a marble drawn 'at random' is white and odd numbered.

  1. A \( \frac{1}{7} \)
  2. B \( \frac{1}{5} \)
  3. C \( \frac{1}{9} \)
  4. D \( \frac{1}{6} \)
Verified Solution

Answer & Solution

Correct Answer

(B) \( \frac{1}{5} \)

Step-by-step Solution

Detailed explanation

Number of red marbles are \(6(1\) to 6\()\), number of white marbles are \(4(12\) to 15\()\). So,
R1, R2, R3, R4, R5, R6, W12, W13, W14, W15
Total number of marbles are 10.
We have, white + odd = W13, W15
So, required probability is
\(\frac{2}{10}=\frac{1}{5}\)