KCET · Chemistry · Solutions
Which of the following aqueous solutions will exhibit highest boiling point?
- A \(0.01 \mathrm{M}\) urea
- B \(0.01 \mathrm{M} \mathrm{KNO}_{3}\)
- C \(0.01 \mathrm{M} \mathrm{Na}_{2} \mathrm{SO}_{4}\)
- D \(0.015 \mathrm{M} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\)
Answer & Solution
Correct Answer
(C) \(0.01 \mathrm{M} \mathrm{Na}_{2} \mathrm{SO}_{4}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
\mathrm{NH}_{2} \mathrm{CONH}_{2} & \longrightarrow \text { no dissociation } \\
\mathrm{KNO}_{3} & \longrightarrow \mathrm{K}^{+}+\mathrm{NO}_{3}^{-} ; \quad i=2 \\
\mathrm{Na}_{2} \mathrm{SO}_{4} & \longrightarrow 2 \mathrm{Na}^{+}+\mathrm{SO}_{4}^{2-} ; \quad i=3 \\
\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} & \longrightarrow \text { no dissociation }
\end{aligned}\)
As \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) gives maximum particles, i.e., 3 on dissociation boiling point is maximum for \(\mathrm{Na}_{2} \mathrm{SO}_{4}\).
\mathrm{NH}_{2} \mathrm{CONH}_{2} & \longrightarrow \text { no dissociation } \\
\mathrm{KNO}_{3} & \longrightarrow \mathrm{K}^{+}+\mathrm{NO}_{3}^{-} ; \quad i=2 \\
\mathrm{Na}_{2} \mathrm{SO}_{4} & \longrightarrow 2 \mathrm{Na}^{+}+\mathrm{SO}_{4}^{2-} ; \quad i=3 \\
\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} & \longrightarrow \text { no dissociation }
\end{aligned}\)
As \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) gives maximum particles, i.e., 3 on dissociation boiling point is maximum for \(\mathrm{Na}_{2} \mathrm{SO}_{4}\).
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