KCET · Chemistry · Structure of Atom
The correct set of four quantum numbers for the outermost electron of sodium \((Z=11)\) is
- A \(3,1,1, \frac{1}{2}\)
- B \(3,2,1, \frac{1}{2}\)
- C \(3,0,0, \frac{1}{2}\)
- D \(3,1,0, \frac{1}{2}\)
Answer & Solution
Correct Answer
(C) \(3,0,0, \frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\[
{ }_{11} \mathrm{Na}=1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{1}
\]
For \(3 s^{1}\),
\[
\mathrm{n}=3, \quad \mathrm{l}=0, \quad \mathrm{~m}=0, \quad \mathrm{~s}=\frac{1}{2}
\]
{ }_{11} \mathrm{Na}=1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{1}
\]
For \(3 s^{1}\),
\[
\mathrm{n}=3, \quad \mathrm{l}=0, \quad \mathrm{~m}=0, \quad \mathrm{~s}=\frac{1}{2}
\]
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