KCET · Chemistry · Electrochemistry
At a particular temperature, the ratio of molar conductance to specific conductance of \( 0.01 \mathrm{M} \)
\( \mathrm{NaCl} \) solution IS
- A \( 10^{5} \mathrm{~cm}^{3} \mathrm{~mol}^{-1} \)
- B \( 10^{3} \mathrm{~cm}^{3} \mathrm{~mol}^{-1} \)
- C \( 10 \mathrm{~cm}^{3} \mathrm{~mol}^{-1} \)
- D \( 10^{5} \mathrm{~cm}^{2} \mathrm{~mol}^{-1} \)
Answer & Solution
Correct Answer
(A) \( 10^{5} \mathrm{~cm}^{3} \mathrm{~mol}^{-1} \)
Step-by-step Solution
Detailed explanation
Using the formula, \( \Lambda_{m}=\frac{K \times 1000}{C} \)
\( \frac{\Lambda_{m}}{K}=\frac{1000}{C} \)
\( =\frac{1000}{0.01}=10^{5} \mathrm{~cm}^{3} \mathrm{~mol}^{-1} \)
\( \frac{\Lambda_{m}}{K}=\frac{1000}{C} \)
\( =\frac{1000}{0.01}=10^{5} \mathrm{~cm}^{3} \mathrm{~mol}^{-1} \)
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