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Molarity of a given orthophosphoric acid solution is \(3 \mathrm{M}\). It's normality is
- A \(9 \mathrm{~N}\)
- B \(0.3 \mathrm{~N}\)
- C \(3 \mathrm{~N}\)
- D \(1 \mathrm{~N}\)
Answer & Solution
Correct Answer
(A) \(9 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Orthophosphoric acid \(\left(\mathrm{H}_{3} \mathrm{PO}_{4}\right)\) is a tribasic acid
\(\because \quad\) Normality \(=\) Molarity \(\times\) basicity \(\begin{aligned} \therefore \quad \text { Normality } &=3 \mathrm{M} \times 3 \\ &=9 \mathrm{~N} \end{aligned}\)
\(\because \quad\) Normality \(=\) Molarity \(\times\) basicity \(\begin{aligned} \therefore \quad \text { Normality } &=3 \mathrm{M} \times 3 \\ &=9 \mathrm{~N} \end{aligned}\)
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