KCET · Maths · Vector Algebra
If the volume of the parallelopiped with \(\overrightarrow{\mathbf{a}}, \overrightarrow{\mathbf{b}}\) and \(\overrightarrow{\mathbf{c}}\) as coterminous edges is \(40 \mathrm{cu}\) unit, then the volume of the parallelopiped having \(\overrightarrow{\mathbf{b}}+\overrightarrow{\mathbf{c}}, \overrightarrow{\mathbf{c}}+\overrightarrow{\mathbf{a}}\) and \(\overrightarrow{\mathbf{a}}+\overrightarrow{\mathbf{b}}\) as coterminous edges in cubic unit is
- A 80
- B 120
- C 160
- D 40
Answer & Solution
Correct Answer
(A) 80
Step-by-step Solution
Detailed explanation
Given, volume of parallelopiped
\[
[\overrightarrow{\mathbf{a}} \overrightarrow{\mathbf{b}} \overrightarrow{\mathbf{c}}]=40
\]
\(\therefore\) Volume of parallelopiped
\(=\left[\begin{array}{lll}\overrightarrow{\mathbf{b}}+\overrightarrow{\mathbf{c}} & \overrightarrow{\mathbf{c}}+\overrightarrow{\mathbf{a}} & \overrightarrow{\mathbf{a}}+\overrightarrow{\mathbf{b}}\end{array}\right]\)
\(=2[\overrightarrow{\mathbf{a}} \overrightarrow{\mathbf{b}} \overrightarrow{\mathbf{c}}]\)
\(=2 \times 40=80 \mathrm{cu}\) unit
\[
[\overrightarrow{\mathbf{a}} \overrightarrow{\mathbf{b}} \overrightarrow{\mathbf{c}}]=40
\]
\(\therefore\) Volume of parallelopiped
\(=\left[\begin{array}{lll}\overrightarrow{\mathbf{b}}+\overrightarrow{\mathbf{c}} & \overrightarrow{\mathbf{c}}+\overrightarrow{\mathbf{a}} & \overrightarrow{\mathbf{a}}+\overrightarrow{\mathbf{b}}\end{array}\right]\)
\(=2[\overrightarrow{\mathbf{a}} \overrightarrow{\mathbf{b}} \overrightarrow{\mathbf{c}}]\)
\(=2 \times 40=80 \mathrm{cu}\) unit
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