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KCET · Maths · Complex Number

If \(x+i y=(-1+i \sqrt{3})^{2010}\), then \(x\) is

  1. A \(-2^{2010}\)
  2. B \(2^{2010}\)
  3. C 1
  4. D \(-1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2^{2010}\)

Step-by-step Solution

Detailed explanation

\(x+i y=(-1+i \sqrt{3})^{2010}\)
\(\Rightarrow \quad x+i y=(2)^{2010}\left(\frac{-1+i \sqrt{3}}{2}\right)^{2010}\)
\(\Rightarrow \quad(x+i y)=(2)^{2010} \omega^{2010} \quad\left(\because \omega=\frac{-1+i \sqrt{3}}{2}\right)\)
\(\Rightarrow \quad(x+i y)=(2)^{2010}\left(\omega^{3}\right)^{670} \quad\left(\because \omega^{3}=1\right)\)
\(\Rightarrow \quad(x+i y)=(2)^{2010}(1)^{670}=2^{2010}+i \cdot 0\)
On comparing real part
\(\Rightarrow \quad \quad x=2010\)