KCET · Chemistry · Solid State
If ' \(a\) ' stands for the edge length of the cubic systems. The ratio of radii in simple cubic, body centred cubic and face centred cubic unit cells is
- A \(1 a: \sqrt{3} a: \sqrt{2} a\)
- B \(\frac{1}{2} a: \frac{\sqrt{3}}{4} a: \frac{1}{2 \sqrt{2}} a\)
- C \(\frac{1}{2} a: \frac{\sqrt{3}}{2} a: \frac{\sqrt{2}}{2} a\)
- D \(\frac{1}{2} a: \sqrt{3} a: \frac{1}{\sqrt{2}} a\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2} a: \frac{\sqrt{3}}{4} a: \frac{1}{2 \sqrt{2}} a\)
Step-by-step Solution
Detailed explanation
For simple cube,
\(r=\frac{a}{2}\)
For bcc, \(r=\frac{a \sqrt{3}}{4}\)
For \(f c c, r=\frac{a}{2 \sqrt{2}}\)
where, \(a=\) edge length, \(r=\) radius
Thus, ratio of radii of the three unit cells will be
\(\frac{1}{2} a: \frac{\sqrt{3}}{4} a: \frac{1}{2 \sqrt{2}} a\)
\(r=\frac{a}{2}\)
For bcc, \(r=\frac{a \sqrt{3}}{4}\)
For \(f c c, r=\frac{a}{2 \sqrt{2}}\)
where, \(a=\) edge length, \(r=\) radius
Thus, ratio of radii of the three unit cells will be
\(\frac{1}{2} a: \frac{\sqrt{3}}{4} a: \frac{1}{2 \sqrt{2}} a\)
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