KCET · Chemistry · Electrochemistry
An aqueous solution of \( \mathrm{CuSO}_{4} \) is subjected to electrolysis using inert electrodes. The \( \mathrm{pH} \) of
the solution will
- A decrease
- B increase or decrease depending on the strength of the current
- C increase
- D remains unchanged
Answer & Solution
Correct Answer
(A) decrease
Step-by-step Solution
Detailed explanation
(A)
At cathode \(: \mathrm{Cu}^{+2}(a q)+2 e^{-} \rightarrow \mathrm{Cu}(\mathrm{s})\)
At anode \(: 2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{O}_{2}+4 \mathrm{H}^{+}+4 e^{-}\)
Production of \(\mathrm{H}^{+}\)ions will decrease \(\mathrm{pH}\)
At cathode \(: \mathrm{Cu}^{+2}(a q)+2 e^{-} \rightarrow \mathrm{Cu}(\mathrm{s})\)
At anode \(: 2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{O}_{2}+4 \mathrm{H}^{+}+4 e^{-}\)
Production of \(\mathrm{H}^{+}\)ions will decrease \(\mathrm{pH}\)
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