KCET · Chemistry · Redox Reactions
Given below are two statements.
Statement-I: In \(\text{H}_2\text{O}_2\), each oxygen atom is assigned an oxidation number of \(-1\), in \(\text{RbO}_2\) each oxygen atom is assigned an oxidation number of \(-\dfrac{1}{2}\).
Statement-II: Representation of \(\text{HAuCl}_4\) and \(\text{MnO}_2\) in stock notation is \(\text{HAu(III)Cl}_4\) and \(\text{Mn(II)O}_2\), respectively.
Examine the above statements and choose the correct answer.
- A Both Statement I and Statement II are correct
- B Both Statement I and Statement II are incorrect
- C Statement I is correct but Statement II is incorrect
- D Statement I is incorrect but Statement II is correct
Answer & Solution
Correct Answer
(C) Statement I is correct but Statement II is incorrect
Step-by-step Solution
Detailed explanation
In \(\text{H}_2\text{O}_2\), the oxidation state of hydrogen is \(+1\). Let the oxidation state of oxygen be \(x\).
\(2(+1) + 2x = 0 \Rightarrow x = -1\)
In \(\text{RbO}_2\), rubidium is an alkali metal with an oxidation state of \(+1\). Let the oxidation state of oxygen be \(y\).
\(+1 + 2y = 0 \Rightarrow y = -\dfrac{1}{2}\)
Thus, Statement-I is correct.
In \(\text{HAuCl}_4\), the oxidation state of Au is \(+3\). Its Stock notation is \(\text{HAu(III)Cl}_4\).
In \(\text{MnO}_2\), the oxidation state of Mn is \(+4\). Its Stock notation is \(\text{Mn(IV)O}_2\), not \(\text{Mn(II)O}_2\).
Thus, Statement-II is incorrect.
Answer: Statement I is correct but Statement II is incorrect
\(2(+1) + 2x = 0 \Rightarrow x = -1\)
In \(\text{RbO}_2\), rubidium is an alkali metal with an oxidation state of \(+1\). Let the oxidation state of oxygen be \(y\).
\(+1 + 2y = 0 \Rightarrow y = -\dfrac{1}{2}\)
Thus, Statement-I is correct.
In \(\text{HAuCl}_4\), the oxidation state of Au is \(+3\). Its Stock notation is \(\text{HAu(III)Cl}_4\).
In \(\text{MnO}_2\), the oxidation state of Mn is \(+4\). Its Stock notation is \(\text{Mn(IV)O}_2\), not \(\text{Mn(II)O}_2\).
Thus, Statement-II is incorrect.
Answer: Statement I is correct but Statement II is incorrect
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\begin{array}{|l|l|l|l|}\hline & \text{List-I (Types of redox reactions)} & & \text{List-II (Examples)} \\\hline \text{a}. & \text{Combination reaction} & \text{(i)} & \mathrm{Cl}_{2(\mathrm{~g})}+2 \mathrm{Br}_{(\mathrm{aq})}^{-} \rightarrow 2 \mathrm{Cl}_{(\mathrm{aq})}^{-}+\mathrm{Br}_{2(\mathrm{l})} \\\hline \text{b.} & \text{Decomposition reaction} & \text{(ii)} & 2 \mathrm{H}_2 \mathrm{O}_{2(\mathrm{aq})} \rightarrow 2 \mathrm{H}_2 \mathrm{O}_{(1)}+\mathrm{O}_{2(\mathrm{~g})} \\\hline \text{c.} & \text{Displacement reaction} & \text{(iii)} & \mathrm{CH}_{4(\mathrm{~g})}+2 \mathrm{O}_{2(\mathrm{~g})} \xrightarrow{\Delta} \mathrm{CO}_{2(\mathrm{~g})}+2 \mathrm{H}_2 \mathrm{O}_{(1)} \\\hline \text{d.} & \text{Disproportionation reaction} & \text{(iv)} & \mathrm{H}_2 \mathrm{O}_{(1)} \xrightarrow{\Delta} 2 \mathrm{H}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} \\\hline\end{array}
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