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KCET · Chemistry · Redox Reactions

Given below are two statements.
Statement-I: In \(\text{H}_2\text{O}_2\), each oxygen atom is assigned an oxidation number of \(-1\), in \(\text{RbO}_2\) each oxygen atom is assigned an oxidation number of \(-\dfrac{1}{2}\).
Statement-II: Representation of \(\text{HAuCl}_4\) and \(\text{MnO}_2\) in stock notation is \(\text{HAu(III)Cl}_4\) and \(\text{Mn(II)O}_2\), respectively.
Examine the above statements and choose the correct answer.

  1. A Both Statement I and Statement II are correct
  2. B Both Statement I and Statement II are incorrect
  3. C Statement I is correct but Statement II is incorrect
  4. D Statement I is incorrect but Statement II is correct
Verified Solution

Answer & Solution

Correct Answer

(C) Statement I is correct but Statement II is incorrect

Step-by-step Solution

Detailed explanation

In \(\text{H}_2\text{O}_2\), the oxidation state of hydrogen is \(+1\). Let the oxidation state of oxygen be \(x\).

\(2(+1) + 2x = 0 \Rightarrow x = -1\)

In \(\text{RbO}_2\), rubidium is an alkali metal with an oxidation state of \(+1\). Let the oxidation state of oxygen be \(y\).

\(+1 + 2y = 0 \Rightarrow y = -\dfrac{1}{2}\)

Thus, Statement-I is correct.

In \(\text{HAuCl}_4\), the oxidation state of Au is \(+3\). Its Stock notation is \(\text{HAu(III)Cl}_4\).

In \(\text{MnO}_2\), the oxidation state of Mn is \(+4\). Its Stock notation is \(\text{Mn(IV)O}_2\), not \(\text{Mn(II)O}_2\).

Thus, Statement-II is incorrect.

Answer: Statement I is correct but Statement II is incorrect
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