KCET · Chemistry · Chemical Equilibrium
\(2 \mathrm{HI}(\mathrm{g}) \rightleftharpoons \mathrm{H}_{2}(\mathrm{~g})+\mathrm{I}_{2}(\mathrm{~g})\)
The equilibrium constant of the above reaction is \(6.4\) at \(300 \mathrm{~K}\). If \(0.25\) mole each of \(\mathrm{H}_{2}\) and \(\mathrm{I}_{2}\) are added to the system, the equilibrium constant will be
- A \(6.4\)
- B \(0.8\)
- C \(3.2\)
- D \(1.6\)
Answer & Solution
Correct Answer
(A) \(6.4\)
Step-by-step Solution
Detailed explanation
The value of equilibrium constant remains constant for a given reaction at constant temperature.
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